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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum of nn terms of the series 41⋅2⋅3+52⋅3⋅4+63⋅4⋅5+…\frac{4}{1 \cdot 2 \cdot 3}+\frac{5}{2 \cdot 3 \cdot 4}+\frac{6}{3 \cdot 4 \cdot 5}+\ldots is
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Correct option: C
54−2n+52(n+1)(n+2)\frac{5}{4}-\frac{2 n+5}{2(n+1)(n+2)}
Option D (54−2n+52(n+1)(n+2)\frac{5}{4}-\frac{2 n+5}{2(n+1)(n+2)}) is correct because the sum of n terms of the series is calculated to be in this form by partial fraction decomposition.

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