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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1
An electromagnetic wave has electric field given by E⃗=(9.6j^)sin⁡[2π{30×106t−110x}],x\vec{E}=(9.6 \hat{j}) \sin \left[2 \pi\left\{30 \times 10^6 t-\frac{1}{10} x\right\}\right], x and tt are in SI units. The maximum magnetic field is
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Correct option: A
3.2×10−93.2 \times 10^{-9}
Option A (3.2×10−93.2 \times 10^{-9}) is incorrect. The correct answer is 3.2×10−83.2 \times 10^{-8} because the maximum magnetic field is found using B=EcB = \frac{E}{c}.

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