The mean of the series ${x_1},{x_2}, \ldots ,{x_n}$ is $\bar X.$ If ${x_2}$ is replaced by $\lambda $, then the new mean is

$\frac{{\bar X - {x_2} - \lambda }}{n}$

$\frac{{\left( {n - 1} \right)\bar X + \lambda }}{n}$

JEE MATHEMATICS MCQ: STATISTICS

1 Easy

1 of 1

Application +4 | -1

The mean of the series

{x_1},{x_2}, \ldots ,{x_n}

\bar X.

{x_2}

is replaced by

\lambda

, then the new mean is

View answer and explanation

Correct option: D

\frac{{n\;\bar X - {x_2} + \lambda }}{n}

Option D (

\frac{{n\;\bar X - {x_2} + \lambda }}{n}

) is correct because it represents the new mean after replacing one of the values in the series.

Practice All Chapter MCQs →

{x_1},{x_2}, \ldots ,{x_n}

\bar X,

{x_i} + 2\;i;i = 1,\;2, \ldots ,n

1,3,5, x, y

-2,