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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Number of electrons flowing per second is a conductor carrying a current of 9 A9 {~A} is_____
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Correct option: B
5.6×10195.6 \times 10^{19}
Option B (5.6×10195.6 \times 10^{19}) is correct because it is calculated using the formula I=ne/tI = ne/t where n is the number of electrons.

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