Force $F$ is given in terms of time $t$ and distance $x$ by $F = a\sin ct + b\cos \,dx$, then the dimension of $a/b$ is:-

$\left[ {{M^0}{L^1}{T^{ - 1}}} \right]$

$\left[ {{M^1}{L^1}{T^{ - 1}}} \right]$

$\left[ {{M^1}{L^0}{T^{ - 1}}} \right]$

NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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Analyzing +4 | -1

Force

F

is given in terms of time

t

and distance

x

F = a\sin ct + b\cos \,dx

, then the dimension of

a/b

is:-

View answer and explanation

Correct option: C

\left[ {{M^0}{L^0}{T^0}} \right]

Option C ([

{M^0}{L^0}{T^0}

]) is correct because the arguments of sine and cosine functions must be dimensionless, and therefore a/b is dimensionless.