JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

\lim _{x \rightarrow \frac{\pi}{6}}\left(\frac{2 \sin ^2 x+\sin x-1}{2 \sin ^2 x-3 \sin x+1}\right)=

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Correct option: C

-3

Option C (-3) is correct because by factoring the numerator and denominator and simplifying, the limit evaluates to -3.

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