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JEE CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

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Analyzing +4 | -1
Which one of the following does not have sp2s p^2-hybridized carbon?
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Correct option: C
CH3−C≡N\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{N}
The correct answer is C (CH3−C≡N\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{N}) because the carbon atom bonded to the nitrogen atom is sp hybridized, not sp2.

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