JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

5\left( {{{\tan }^2}x - {{\cos }^2}x} \right) = 2\cos 2x + 9

, then the value of

\cos \,4x

View answer and explanation

Correct option: D

- \frac{7}{9}

Option D (

- \frac{7}{9}

) is correct because it is the value of

\cos 4x

calculated from the given trigonometric equation.

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