In the formation of ${\rm{S}}{{\rm{O}}_3}$ by ${\rm{S}}{{\rm{O}}_2}$ and ${{\rm{O}}_2}$ using NO as catalyst, the catalytic action of ${\rm{N}}{{\rm{O}}_2}$ is evidenced by :

NEET UG CHEMISTRY MCQ: SURFACE CHEMISTRY

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Understanding +4 | -1

In the formation of

\mathrm{S}{\mathrm{O}_3}

\mathrm{S}{\mathrm{O}_2}

and

{\mathrm{O}_2}

using NO as catalyst, the catalytic action of

\mathrm{N}{\mathrm{O}_2}

is evidenced by :

View answer and explanation

Correct option: C

Brown vapours

Option C (Brown vapours) is correct because

NO_2

is a brown gas and its presence indicates the catalytic action.

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10^{-3} \mathrm{M}

1 \mathrm{~mm}^3

2 \times 10^{13}

\mathrm{N}_{\mathrm{A}}=6 \times 10^{23}

\log \frac{{x}}{{m}}

\log {P}

\theta=45^{\circ}

0.5

\log {k}= 0.699,

\mathrm{g}

\log \;x/m\mathrm{ } \;vs.

\log \;P

19\;\mathrm{g/c}{\mathrm{m}^3}

{1.9 \times {{10}^{ - 4}}\;\mathrm{g}}

10\;\mathrm{ }nm

m{m^3}