In the reaction, ${\rm{VO}} + {\rm{F}}{{\rm{e}}_2}{{\rm{O}}_3} \to {\rm{FeO}} + {{\rm{V}}_2}{{\rm{O}}_5}{\rm{.}}$. The eq.wt. of ${{\rm{V}}_2}{{\rm{O}}_5}$ is equal to its :

NEET UG CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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In the reaction,

\mathrm{VO} + \mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} \to \mathrm{FeO} + {\mathrm{V}_2}{\mathrm{O}_5}\mathrm{.}

. The eq.wt. of

{\mathrm{V}_2}{\mathrm{O}_5}

is equal to its :

View answer and explanation

Correct option: C

mol.\mathrm{ }wt./6

Option C (

mol.\mathrm{ }wt./6

) is correct because the equivalent weight is the molecular weight divided by the change in oxidation state of Vanadium, which is 6.