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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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In a thermo-couple, one junction which is at 0 ∘C0\,^\circ C and the othe at t  ∘Ct{\mkern 1mu} {\mkern 1mu} ^\circ C the emf is given by E=at2−bt2E = a{t^2} - b{t^2}. The neutral temperature is given by
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Correct option: B
2  a/3 b2\,\,a/3\,b
Option B (2  a/3 b2\,\,a/3\,b) is correct because the neutral temperature is found by setting the derivative of the emf with respect to temperature equal to zero.

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