JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

1 of 1

Application +4 | -1

The angle between the tangents to the curve

y=x^2-5 x+6

at the point

(2,0)

and

(3,0)

, is

View answer and explanation

Correct option: B

\pi / 2

Option B (

\pi / 2

) is correct because the product of the slopes of the tangents at the given points is -1, indicating perpendicularity.

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x y=1-y

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y^3-3 x y+2=0

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\mathrm{C}

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y-e^{x y}+x=0

y = f\left( x \right)

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x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z