NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Easy

1 of 1

Application +4 | -1

For strong acid strong base neutralisation energy for 1 mole

{H}_2 {O}

formation is

-57.1 \mathrm{~kJ}

. If

0.25

mole of strong monoprotic acid is reacted with

0.5

mole of strong base then enthalpy of neutralisation is

View answer and explanation

Correct option: A

-(0.25 \times 57.1)

Option A (-(0.25 x 57.1)) is correct because the enthalpy of neutralization is proportional to the moles of water formed, which is limited by the limiting reactant (acid).

More Questions from THERMODYNAMICS

Practice All Chapter MCQs →

The internal energy of one mole of a gas is: An ideal gas is allowed to expand both reversibly and irreversibly in an isolated system. If

{T_i}

is the initial temperature and

{T_f}

is the final temperature, which of the following statements is correct? For which of the process, ∆S is negative? The work done by a weightless piston in causing an expansion ∆V (at constant temperature), when the opposing pressure, P is variable, is given by: Assertion :- At constant pressure of the change

\mathrm{H}_2 \mathrm{O}(\mathrm{s}) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{g})

work done is negative.

Reason :- During phase transition work done is always negative. For the reaction,

\mathrm{X}_2 \mathrm{O_4(l}) \longrightarrow 2 \mathrm{XO}_2(\mathrm{g}), \Delta U=2.1 \mathrm{~kcal}, \Delta S=20 \mathrm{~cal} \mathrm{~K}^{-1}

300 \mathrm{~K}

. Hence,

\Delta G