Work done in rising temperature of five mole of Helium adiabatically through $\theta^{\circ} {C}$ is ${W}$. Then the work done in an isobaric process of the sample for same change of temperature is

NEET UG PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

Work done in rising temperature of five mole of Helium adiabatically through

\theta^{\circ} {C}

{W}

. Then the work done in an isobaric process of the sample for same change of temperature is

View answer and explanation

Correct option: D

-\frac{2 W}{3}

Option D (

-\frac{2 W}{3}

) is correct because the ratio of work done in the isobaric process to the adiabatic process is -2/3 based on the specific heat capacities.