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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Analyzing +4 | -1
Bond order of N2+N_2^{+}and N2−N_2^{-}are same. Which relation is correct for N2+N_2^{+}and N2−?N_2^{-}?
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Correct option: B
Bond energy of N2+>N_2^{+}> Bond energy of N2−N_2^{-}
Option B is correct because the bond energy of N2+N_2^+ is greater than the bond energy of N2−N_2^- due to the electron being removed from a bonding orbital in N2+N_2^+ and added to an antibonding orbital in N2−N_2^-.

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