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JEE MATHEMATICS MCQ: STATISTICS

1 Easy
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Application +4 | -1
The variance of the first nn natural numbers is
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Correct option: A
(n2−112)\left( {\frac{{{n^2} - 1}}{{12}}} \right)
Option A ((n2−112)\left( {\frac{{{{{n^2} - 1}}}}{{{{12}}}}} \right)) is correct because it is the formula for the variance of the first n natural numbers.

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