Consider the following pairs of electrons $\begin{array}{*{20}{c}} {{\rm{(A)}}\,\,{\rm{(a)}}\,{\rm{n = 3,}}\,\,{\rm{l = 1,}}\,{{\rm{m}}_{\rm{l}}}{\rm{ = 1,}}\,\,{{\rm{m}}_{\rm{s}}}{\rm{ = + }}\frac{{\rm{1}}}{{\rm{2}}}}\\ {\,\,\,\,\,\,\,\,\,\,\,{\rm{(b)}}\,{\rm{n = 3,}}\,\,{\rm{l = 2,}}\,{{\rm{m}}_{\rm{l}}}{\rm{ = 1,}}\,\,{{\rm{m}}_{\rm{s}}}{\rm{ = + }}\frac{{\rm{1}}}{{\rm{2}}}}\\ {\,{\rm{(B) (a) n = 3,}}\,\,{\rm{l = 2,}}\,{{\rm{m}}_{\rm{l}}}{\rm{ = }} - {\rm{2,}}\,\,{{\rm{m}}_{\rm{s}}}{\rm{ = }} - \frac{{\rm{1}}}{{\rm{2}}}}\\ {\,\,\,\,\,\,\,{\rm{(b) n = 3,}}\,\,{\rm{l = 2,}}\,{{\rm{m}}_{\rm{l}}}{\rm{ = }} - 1{\rm{,}}\,\,{{\rm{m}}_{\rm{s}}}{\rm{ = }} - \frac{{\rm{1}}}{{\rm{2}}}}\\ {{\rm{(C)}}\,{\rm{(a) n = 4,}}\,\,{\rm{l = 2,}}\,{{\rm{m}}_{\rm{l}}}{\rm{ = 2,}}\,\,{{\rm{m}}_{\rm{s}}}{\rm{ = + }}\frac{{\rm{1}}}{{\rm{2}}}}\\ {\,\,\,\,\,\,\,\,{\rm{(b) n = 3,}}\,\,{\rm{l = 2,}}\,{{\rm{m}}_{\rm{l}}}{\rm{ = 2,}}\,\,{{\rm{m}}_{\rm{s}}}{\rm{ = + }}\frac{{\rm{1}}}{{\rm{2}}}} \end{array}$ The pairs of electrons present in degenerate orbitals is/are:

NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

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Analyzing +4 | -1

Consider the following pairs of electrons

\begin{array}{cccccccccccccccccccc} {\mathrm{(A)}\,\,\mathrm{(a)}\,\mathrm{n = 3,}\,\,\mathrm{l = 1,}\,{\mathrm{m}_\mathrm{l}}\mathrm{ = 1,}\,\,{\mathrm{m}_\mathrm{s}}\mathrm{ = + }\frac{\mathrm{1}}{\mathrm{2}}}\\ {\,\,\,\,\,\,\,\,\,\,\,\mathrm{(b)}\,\mathrm{n = 3,}\,\,\mathrm{l = 2,}\,{\mathrm{m}_\mathrm{l}}\mathrm{ = 1,}\,\,{\mathrm{m}_\mathrm{s}}\mathrm{ = + }\frac{\mathrm{1}}{\mathrm{2}}}\\ {\,\mathrm{(B) (a) n = 3,}\,\,\mathrm{l = 2,}\,{\mathrm{m}_\mathrm{l}}\mathrm{ = } - \mathrm{2,}\,\,{\mathrm{m}_\mathrm{s}}\mathrm{ = } - \frac{\mathrm{1}}{\mathrm{2}}}\\ {\,\,\,\,\,\,\,\mathrm{(b) n = 3,}\,\,\mathrm{l = 2,}\,{\mathrm{m}_\mathrm{l}}\mathrm{ = } - 1\mathrm{,}\,\,{\mathrm{m}_\mathrm{s}}\mathrm{ = } - \frac{\mathrm{1}}{\mathrm{2}}}\\ {\mathrm{(C)}\,\mathrm{(a) n = 4,}\,\,\mathrm{l = 2,}\,{\mathrm{m}_\mathrm{l}}\mathrm{ = 2,}\,\,{\mathrm{m}_\mathrm{s}}\mathrm{ = + }\frac{\mathrm{1}}{\mathrm{2}}}\\ {\,\,\,\,\,\,\,\,\mathrm{(b) n = 3,}\,\,\mathrm{l = 2,}\,{\mathrm{m}_\mathrm{l}}\mathrm{ = 2,}\,\,{\mathrm{m}_\mathrm{s}}\mathrm{ = + }\frac{\mathrm{1}}{\mathrm{2}}} \end{array}

The pairs of electrons present in degenerate orbitals is/are:

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Correct option: B

Only B

Only B is correct because degenerate orbitals have the same n and l values. In B, both electrons have n=3 and l=2.