JEE CHEMISTRY MCQ: CHEMICAL KINETICS

1 Medium

1 of 1

Application +4 | -1

In a reaction:

A \to B,

the concentration of ‘

A

’ at time 10 s and 20 s is

2.2\,{\text{mol}}\,{{\text{L}}^{ - 1}}

and

1.1\,{\text{mol}}\,{{\text{L}}^{ - 1}}.

The average rate of the reaction during the time period is

View answer and explanation

Correct option: C

0.11\,{\text{mol}}\,{{\text{L}}^{ - 1}}{{\text{S}}^{ - 1}}

Option C (

0.11\,{\text{mol}}\,{{\text{L}}^{ - 1}}{{\text{S}}^{ - 1}}

) is correct because it is the average rate of the reaction calculated using the change in concentration over the change in time.

More Questions from CHEMICAL KINETICS

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\mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB}

\begin{aligned} & {{\text{A}}_2}\mathop \rightleftharpoons \limits_{{{\text{k}}_{ - 1}}}^{{{\text{k}}_1}} {\text{A}} + {\text{A (fast) }} \\ & \mathrm{A}+\mathrm{B}_2 \xrightarrow{\mathrm{k}_2} \mathrm{AB}+\mathrm{B} \text { (slow) } \\ & \mathrm{A}+\mathrm{B} \rightarrow \mathrm{AB} \text { (fast) } \end{aligned}

k

(Initial\mathrm{ }conc.\mathrm{ } = a)

C_0 \sqrt{T}

C_0

T

100 \mathrm{~kJ/mol}.

75 \%

\log _{10} \frac{K_2}{K_1}

27^{\circ} \mathrm{C}

2.303 \times 8.314=19.147