Skip to main content
Back to MOTION IN A STRAIGHT LINE

JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

1 Medium
1 of 1
Application +4 | -1
A stone is dropped from a rising balloon at a height of 76 m76 \mathrm{~m} above the ground and reaches the ground in 6 s6 \mathrm{~s}. What was the velocity of the balloon when the stone was dropped? [Take g=10 m/s2{g}=10 \mathrm{~m} / \mathrm{s}^2]
View answer and explanation
Correct option: A
(523)m/s\left(\frac{52}{3}\right) \mathrm{m} / \mathrm{s} upwards
Option A (52/3 m/s upwards) is correct because it is the initial upward velocity of the stone calculated using the kinematic equation with the given height, time, and acceleration due to gravity.

More Questions from MOTION IN A STRAIGHT LINE

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.