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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
1.2.3+2.3.4+3.4.5+……+n1.2 .3+2.3 .4+3.4 .5+\ldots \ldots+\mathrm{n} terms -
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Correct option: C
n(n+1)(n+2)(n+3)4\frac{\mathrm{n}(\mathrm{n}+1)(\mathrm{n}+2)(n+3)}{4}
Option C (n(n+1)(n+2)(n+3)4\frac{{n(n+1)(n+2)(n+3)}}{{4}}) is correct because the sum of the series is found by using the formula for summation of consecutive terms.

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