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JEE PHYSICS MCQ: OSCILLATIONS

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Application +4 | -1

Time period of a simple pendulum in a stationary lift is

'T'

If the lift accelerates with

\frac{g}{6}

vertically upwards then the time period will be
(Where

g

= acceleration due to gravity)

View answer and explanation

Correct option: C

\sqrt {\frac{6}{7}} T

Option C (

\sqrt {\frac{6}{7}} T

) is correct because the effective acceleration due to gravity increases when the lift accelerates upwards, thus decreasing the time period.

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