The coordination number and oxidation number of $X$ in the following compound $\left[ {X\left( {{\rm{S}}{{\rm{O}}_4}} \right){{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_5}} \right]{\rm{Cl\;}}$ will be

JEE CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

1 Easy

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Application +4 | -1

The coordination number and oxidation number of

X

in the following compound

\left[ {X\left( {\mathrm{S}{\mathrm{O}_4}} \right){{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_5}} \right]\mathrm{Cl\;}

will be

View answer and explanation

Correct option: C

6 and 3

Option C (6 and 3) is correct because the coordination number is the number of ligands attached to the metal, and the oxidation number is calculated based on the charges of the ligands and counter-ion.

More Questions from CO-ORDINATION COMPOUNDS

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Which has maximum paramagnetic character? Ionization of

\mathrm{K}\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right]

will give: The cation that does not form an ammine complex with excess of ammonia is: The complexes

\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

are example for isomerism The correct name of

\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]\left[\mathrm{PtCl}_4\right]

is: Which of the following pairs of isomers and types of isomerism are correctly matched?

(I)

\left[{Co}\left({NH}_3\right)_5\left({NO}_2\right)\right] {Cl}_2

and

\left[{Co}\left({NH}_3\right)_5({ONO})\right] {Cl}_2 \ldots \ldots \ldots

Linkage

(II)

\left[{Cu}\left({NH}_3\right)_4\right]\left[{PtCl}_4\right] \,\, \& \,\, \left[{Pt}\left({NH}_3\right)_4\right]\left[{CuCl}_4\right] \ldots \ldots \ldots

Coordinations

(III)

\left[{Pt}\left({NH}_3\right)_4 {Cl}_2\right] {Br}_2 \, \, \& \, \, \left[{Pt}\left({NH}_3\right)_4 {Br}_2\right]{Cl}_2 \ldots \ldots \ldots

Ionization

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