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JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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Analyzing +4 | -1
Formaldehyde and formic acid can be distinguished by:
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Correct option: D
NaHCO3\mathrm{NaHC}{\mathrm{O}_3}
Option D (NaHCO3\mathrm{NaHC}{\mathrm{O}_3}) is correct because formic acid reacts with sodium bicarbonate to produce carbon dioxide gas, while formaldehyde does not.

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