Back to MOTION IN A STRAIGHT LINE
JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE
1
Medium
1 of 1
Application
+4 | -1
From the top of tower, a particle is thrown vertically downwards with a velocity of . The ratio of the distances covered by it in the 3rd and 2nd seconds of the motion is : (Take ) :
View answer and explanation
Correct option: B
0.295138889
Option B (07:05) is correct because it is the ratio of distances calculated using the formula for distance covered in the nth second.
More Questions from MOTION IN A STRAIGHT LINE
Practice All Chapter MCQs →
Assertion: In a free fall, the initial velocity of a body may not be zero.
Reason: Free fall means the vertical acceleration of the body is equal to . A ball is thrown vertically upward with speed 15 m/s and it returns to the ground with speed 10 m/s as a constant air resistance acts. The maximum height attained by the ball is Which of the following is not a derived quantites? Assertion: If a body is dropped from the top of a tower of height and another body is thrown up simultaneously with velocity from the foot of the tower, then both of them would meet after a time .
Reason: For a body projected upwards, the distance covered by the body in the last second of its upward journey is always irrespective of velocity of projection. A particle is having uniform acceleration. If its displacement from to second is and change in velocity is . Find its displacement (in ) in second. An aeroplane flies 400m north and 300m south and then flies 1200m upwards, then net displacement is
Reason: Free fall means the vertical acceleration of the body is equal to . A ball is thrown vertically upward with speed 15 m/s and it returns to the ground with speed 10 m/s as a constant air resistance acts. The maximum height attained by the ball is Which of the following is not a derived quantites? Assertion: If a body is dropped from the top of a tower of height and another body is thrown up simultaneously with velocity from the foot of the tower, then both of them would meet after a time .
Reason: For a body projected upwards, the distance covered by the body in the last second of its upward journey is always irrespective of velocity of projection. A particle is having uniform acceleration. If its displacement from to second is and change in velocity is . Find its displacement (in ) in second. An aeroplane flies 400m north and 300m south and then flies 1200m upwards, then net displacement is
