JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Analyzing +4 | -1

The value of

a^x-b^y

is (where

x=\sqrt{\log _a b}

and

y=\sqrt{\log _b a}, a>0, b>0

and

a, b \neq 1)

View answer and explanation

Correct option: C

Option C (0) is correct because by substituting the values of x and y, we find that a^x = b^y, thus a^x - b^y = 0.

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