JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

1 of 1

Application +4 | -1

If the polar with respect to

{y^2} = 4ax

touches the ellipse

\frac{{{x^2}}}{{{\alpha ^2}}} + \frac{{{y^2}}}{{{\beta ^2}}} = 1,

the locus of its pole is

View answer and explanation

Correct option: A

\frac{{{x^2}}}{{{\alpha ^2}}} - \frac{{{y^2}}}{{\left( {4{a^2}{\alpha ^2}/{\beta ^2}} \right)}} = 1

Option A (

\frac{{{x^2}}}{{{\alpha ^2}}} - \frac{{{y^2}}}{{\left( {4{a^2}{\alpha ^2}/{\beta ^2}} \right)}} = 1

) is correct because it represents the locus of the pole when the polar with respect to the parabola touches the given ellipse.

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O