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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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n identical mercury droplets charged to the same potential VV coalesce to form a single bigger drop. The potential of new drop will be
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Correct option: D
n2/3V{n^{2/3}}V
Option D (n2/3V{n^{2/3}}V) is correct because the potential of the new drop is proportional to n2/3n^{2/3} times the potential of the small droplets.

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