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JEE CHEMISTRY MCQ: HYDROCARBONS

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Major product formed in the following reaction is
CH3−CH=CH−CH∣CH3−CH3→HBrC{H_3} - CH = CH - \mathop {CH}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {C{H_3}} \end{array}} - C{H_3}\xrightarrow{{HBr}}
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Correct option: D
CH3−CH2−CH2−Br∣C∣CH3−CH3C{H_3} - C{H_2} - C{H_2} - \begin{array}{cccccccccccccccccccc} {Br} \\ | \\ C \\ | \\ {C{H_3}} \end{array} - C{H_3}
Option D (CH3−CH2−CH2−Br∣C∣CH3−CH3C{H_3} - C{H_2} - C{H_2} - \begin{array}{cccccccccccccccccccc} {Br} \\ | \\ C \\ | \\ {C{H_3}} \end{array} - C{H_3}) is correct because it follows Markovnikov's rule, where the bromine adds to the more substituted carbon.

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