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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
If x=∑n=0∞(−1)ntan⁡2nθx=\sum_{n=0}^{\infty}(-1)^{n} \tan ^{2 n} \theta and y=∑n=0∞cos⁡2nθy=\sum_{n=0}^{\infty} \cos ^{2 n} \theta, for 0<θ<π40<\theta<\frac{\pi}{4}, then:
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Correct option: B
y(1−x)=1y(1-x)=1
Option B (y(1-x)=1) is correct because it is derived by expressing x and y as infinite geometric series and then finding a relationship between them.

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