JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

The value of

\int\limits_{0}^1 \frac{x \mathrm{~d} x}{\left(x^2+1\right)^2}

View answer and explanation

Correct option: D

\frac{1}{4}

Option D (

\frac{{1}}{{4}}

) is correct because by substituting

x^2+1=t

, the integral

\int_0^1 \frac{{x dx}}{{(x^2+1)^2}}

can be easily evaluated to

\frac{{1}}{{4}}

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