JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

A

is the area of the region bounded by the curve

y = \sqrt {3x + 4} ,\;x

-axis and the lines

x = - 1

and

x = 4

and

B

is that area bounded by curve

{y^2} = 3x + 4,\;x

-axis and the liens

x = - 1

and

x = 4

, then

A:B

is equal to

View answer and explanation

Correct option: C

1:2

Option C (

1:2

) is correct because the area B is twice the area A since it includes both the positive and negative square root of the function.

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