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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
If ∫01αeβx2sin⁡(x+k)dx=0\int_0^1 \alpha e^{\beta x^2} \sin (x+k) d x=0 for some α,β∈R\alpha, \beta \in R, α≠0\alpha \neq 0, then the value of kk can belong to the interval
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Correct option: C
[3π4,5π6]\left[\frac{3 \pi}{4}, \frac{5 \pi}{6}\right]
Option C ([3π/4, 5π/6]) is correct because the sine function must change sign within the interval [0, 1] for the integral to be zero.

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