JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Medium

1 of 1

Analyzing +4 | -1

a, a_1, a_2, a_3, \ldots, a_{2 n}, b

are in AP and

a, g_1, g_2, \ldots, g_{2 n}, b

are in GP and

h

is the HM of

a

and

b

, then

\frac{a_1+a_{2 n}}{g_1 g_{2 n}}+\frac{a_2+a_{2 n-1}}{g_2 g_{2 n-1}}+\ldots+\frac{a_n+a_{n+1}}{g_n g_{n+1}}

is equal to

View answer and explanation

Correct option: D

\frac{2 n}{h}

Option D (

\frac{2 n}{h}

) is correct because after using the properties of AP and GP, and the definition of HM, the expression simplifies to

\frac{2 n}{h}

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →

A=\{1,2,3\}, B=\{3,4\}, C=\{4,5,6\}

{A} \cup({B} \cap {C})

A-(B \cap C)

(B \cup C)-A

a,b,c

a,x,b

b,y,c

{x^2},{b^2},{y^2}

P(x)=1-x+x^2-x^3+\ldots+x^{2012}

y

Q(y)=a_0+a_1 y+\ldots+a_{2012} y^{2012}

y=x-2

\sum\limits_{{i=0}}^{2012} a_i

\log \left(\frac{5 c}{a}\right), \log \left(\frac{3 b}{5 c}\right)

\log \left(\frac{a}{3 b}\right)

A P

a, b

G P

a, b, c

\frac{3}{4}