$\mathop {\lim }\limits_{x \to 0} \frac{{{{\sin }^{ - 1}}x - x}}{{{x^3}\cos x}}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

\lim\limits_{x \to 0} \frac{{{{\sin }^{ - 1}}x - x}}{{{x^3}\cos x}}

is equal to

View answer and explanation

Correct option: C

\frac{1}{6}

Option D (None of these) is correct because the limit does not exist since the function oscillates between 0 and 1 as x approaches 0.

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