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JEE PHYSICS MCQ: WAVE OPTICS
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Statement-1: In Young's double slit experiment the two slits are at distance apart. Interference pattern is observed on a screen at distance from the slits. At a point on the screen when it is directly opposite to one of the slits, a dark fringe is observed. Then the wavelength of wave is proportional to square of distance between the two slits.
Statement-2: For a dark fringe intensity is zero.
Statement-2: For a dark fringe intensity is zero.
View answer and explanation
Correct option: C
Statement-1 is true, Statement-2 is false
Option D (Statement-1 is false, Statement-2 is true) is correct because the wavelength is proportional to the square of the distance between the slits, and intensity is indeed zero for a dark fringe.
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