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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
If a,b,ca,b,c the sides of a Δ  ABC\Delta \;ABC are in AP and aa is the smallest side, then cos⁡A\cos A equals
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Correct option: C
4c−3b2c\frac{{4c - 3b}}{{2c}}
Option C 4c−3b2c\frac{{4c - 3b}}{{2c}} is correct because it is derived by using the cosine rule and the given condition that a, b, c are in AP.

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