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JEE MATHEMATICS MCQ: RATE MEASURE

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Application +4 | -1
If x=βˆ’1x = - 1 and x=2x = 2 are extreme points of f(x)=Ξ±log⁑∣x∣+Ξ²x2+x, f(x) = \alpha \log \left| x \right| + \beta {x^2} + x,\, then
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Correct option: C
Ξ±=2,  β=βˆ’12\alpha = 2,\,\,\beta = - \frac{1}{2}
Option C (Ξ±=2, β=βˆ’12\alpha = 2,\,\beta = - \frac{1}{2}) is correct because substituting the extreme points into the derivative of the function and solving the resulting equations gives these values.

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