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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1
Value of I=∫01(2x+1)2dxI=\int\limits_{0}^1(2 x+1)^2 d x is
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Correct option: D
133\frac{13}{3}
Option D (133\frac{13}{3}) is correct because it is the result of correctly evaluating the definite integral of the given function.

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