JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

1 of 1

Application +4 | -1

The foci of the ellipse,

25{\left( {x + 1} \right)^2} + 9{\left( {y + 2} \right)^2} = 225

are at,

View answer and explanation

Correct option: A

\left( { - 1,2} \right)

and

\left( { - 1, - 6} \right)

The correct answer is A ((-1,2) and (-1,-6)) because it correctly identifies the foci of the ellipse after translating the standard ellipse equation.

More Questions from ELLIPSE

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\frac{x^2}{144}+\frac{y^2}{81}=1

m

\mathrm{M}

\mathrm{mM}

P

\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

S

S'.

A

PSS',

A

A

B

(\sqrt{7}, 0)

(-\sqrt{7}, 0)

P

9 x^{2}+16 y^{2}=144

\mathrm{PA}+\mathrm{PB}

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

r

\frac{x^2}{25}+\frac{y^2}{16}=1

P

x=0

Q

R

Q

y=x

Q

R

N P

Q

P

O