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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The orbital angular momentum for an electron revolving in an orbit is h2πl(l+1).\frac{h}{{2\pi }}\sqrt {l\left( {l + 1} \right)} .. Thus momentum for a s-electron is:
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Correct option: D
Zero
Option D (Zero) is correct because the orbital angular momentum depends on the quantum number l, which is 0 for an s-electron, resulting in zero angular momentum.

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