JEE MATHEMATICS MCQ: MAXIMA & MINIMA

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Application +4 | -1

y=a \log |x|+b x^2+x

has its extremum values at

x=-1

and

x=2,

then

View answer and explanation

Correct option: B

a=2, b=\frac{-1}{2}

Option B (

a=2, b=\frac{{-1}}{{2}}

) is correct because it satisfies the conditions for extremum values at x=-1 and x=2.

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