JEE CHEMISTRY MCQ: HYDROCARBONS

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Analyzing +4 | -1

A hydrocarbon has the formula

{\mathrm{C}_3}{\mathrm{H}_4}

. To find out whether it contains two double bonds or triple bonds, the following test is performed:

View answer and explanation

Correct option: A

Passed through ammoniacal

\mathrm{AgN}{\mathrm{O}_3}

Option A is correct because passing the hydrocarbon through ammoniacal AgNO3 will identify terminal alkynes (containing a triple bond at the end of the chain).

More Questions from HYDROCARBONS

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

-bonds presents in Fischer-Tropsch process is used in the manufacture of: