If ${x^2} + 6x - 27 < 0\;$ and $\;{x^2} - 3x - 4 < 0,$ then

JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

{x^2} + 6x - 27 < 0\;

and

\;{x^2} - 3x - 4 < 0,

then

View answer and explanation

Correct option: C

3 < x < 4

Option C (

3 < x < 4

) is correct because it is the intersection of the solution sets of the two inequalities

{x^2} + 6x - 27 < 0

and

{x^2} - 3x - 4 < 0

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