JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1

Let

p=\lim _{x \rightarrow 0^{+}}\left(1+\tan ^2 \sqrt{x}\right)^{\frac{1}{2 x}}

then

\log p

is equal to :

View answer and explanation

Correct option: A

\frac{1}{2}

Option A (

\frac{1}{2}

) is correct because after taking the logarithm and applying L'Hopital's rule, the limit evaluates to

\frac{1}{2}

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