JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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The dimensions of

\left(\mu_0 \varepsilon_0\right)^{-1 / 2}

are

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Correct option: B

\left[\mathrm{LT}^{-1}\right]

Option B ([

\mathrm{LT}^{-1}

]) is correct because

(\mu_0 \varepsilon_0)^{-1 / 2}

represents the speed of light, which has dimensions of length per time.

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{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

{\varepsilon _0}

{\Delta V}

{\Delta t}