JEE PHYSICS MCQ: NUCLEI

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Application +4 | -1

The Binding energy per nucleon of

{ }_3^7 \mathrm{Li}

and

{ }_2^4 \mathrm{He}

nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction

{ }_3^7 \mathrm{Li}+{ }_1^1 \mathrm{H} \rightarrow{ }_2^4 \mathrm{He}+{ }_2^4 \mathrm{He}+\mathrm{Q},

the value of energy 'Q' released is:

View answer and explanation

Correct option: D

17.3 MeV

Option D (17.3 MeV) is correct because it is the energy released in the nuclear reaction, calculated from the difference in binding energies.

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