Skip to main content
Back to MAGNETISM AND MATTER

NEET UG PHYSICS MCQ: MAGNETISM AND MATTER

1 Medium
1 of 1
Application +4 | -1
At a place the angle of dip is 30∘.30^\circ . If the horizontal component of earth’s magnetic field is BH,{B_H}, then the total field intensity is
View answer and explanation
Correct option: B
2BH3\frac{{2{B_H}}}{{\sqrt 3 }}
Option B (2BH3\frac{{2{B_H}}}{{\sqrt 3 }}) is correct because the total field intensity is related to the horizontal component by B=BHcos⁡δB = \frac{B_H}{\cos{\delta}}.

More Questions from MAGNETISM AND MATTER

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.