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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1
If cos⁡θ=12(x+1x)\cos \theta=\frac{1}{2}\left(x+\frac{1}{x}\right), then 12(x2+1x2)\frac{1}{2}\left(x^2+\frac{1}{x^2}\right) is equal to
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Correct option: B
cos⁡2θ\cos 2 \theta
Option B (cos⁡2θ\cos 2 \theta) is correct because it is derived from the given equation by squaring and using the double angle formula for cosine.

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