JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

To determine the Young’s modulus of a wire, the formula is

Y = \frac{F}{A} \times \frac{L}{{\Delta L}}

; where L= length, A= area of cross-section of the wire,

{\Delta L}

= change in length of the wire when stretched with a force F. The conversion factor to change it from CGS to MKS system is

View answer and explanation

Correct option: C

0.1

Option C (0.1) is correct because the conversion factor from CGS to MKS for Young's modulus is 0.1, derived from the unit conversion of dyne/cm² to N/m².

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The method of dimensional analysis can be used to derive which of the following relations? Statement-I: Dimensions of constant of proportionality of constants can be derived from dimensional method
Statement-II: Numerical value of constant of proportionality can be found from experiments only The dimensions of torque are The physical quantity having the dimensions

\left[ {{\mathrm{M}^{ - 1}}{\mathrm{L}^{ - 3}}{\mathrm{A}^2}{T^3}} \right]

is A quantity X is given by

{\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;

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{\varepsilon _0}

is the permittivity of free space, L is a length,

{\Delta V}

is a potential difference and

{\Delta t}

is a time interval. The dimensional formula for X is the same as that of