NEET UG PHYSICS MCQ: WAVES

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Analyzing +4 | -1

The phase difference between the two given waves is

{y_1} = {a_1}\sin \left( {\omega t - \frac{{2\pi }}{\lambda }X} \right)\,\,\,{y_2} = {a_2}\cos \left( {\omega t - \frac{{2\pi }}{\lambda }X + \phi } \right)\,

View answer and explanation

Correct option: C

\frac{\pi }{2} + \left( \phi \right)

Option C (

\frac{\pi }{2} + \left( \phi \right)

) is correct because the phase difference accounts for the cosine function and the additional phase angle

\phi

.

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